6. Resuelve las siguientes ecuaciones quitando para ello el paréntesis antes :a) 3(x – 7) = 5(x – 1) – 4b) 5(2 – x) + 3(x + 6) = 10 – 4(6 + 2x)c) 3x + 8 – 5x – 5 = 2(x + 6) – 7xd) 10(x – 2) = 1?

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C :

a)

3(x - 7) = 5(x - 1) - 4

3x - 21x = 5x - 5 - 4 - 18x - 5x = - 9 - 23x = - 9

x = - 9 / - 23

x = 0, 39

b)

5(2 - x) + 3(x + 6) = 10 - 4(6 + 2x)

10 - 5x + 3x + 18 = 10 - 24 - 8x - 5x + 3x + 8x = 10 - 18 - 10 - 24

6x = - 42

x = - 42 / 6

x = - 7

c)

3x + 8 - 5x - 5 = 2(x + 6) - 7x - 2x + 3 = 2x + 12 - 7x - 2x - 2x + 7x = 12 - 3

3x = 9

x = 9 / 3

x = 3

d)

10(x - 2) = 1

10x - 20 = 1

10x = 1 + 20

x = 21 / 10

x = 2, 1.