Por favor ayundenme x + √4x - 1 = 5?

Resolver.

X + √4x - 1 = 5

x + √4x = 5 + 1

x + √4x = 6

√4x = 6 - x Elevas ambos miembros de la ecuacion al cuadrado.

(√4x)² = (6 - x)² Aplicas producto notable (a - b)² = a² - 2ab + b²

4x = 6² - 2(6)(x) + x² =

4x = 36 - 12x + x²

0 = x² - 12x - 4x + 36

0 = x² - 16x + 36

x² - 16x + 36 = 0

x = [ - b + / - √(b² - 4ac)] / 2a a = 1 b = - 16 c = 36

x = [ - ( - 16) + / - √(( - 16²) - 4(1)(36)] / 2(1)

x = [ 16 + / - √(256 - 144)] / 2

x = [ 16 + / - √112] / 2

x = [ 16 + / - √(4 * 23)] / 2

x = [16 + / - 2√23] / 2 Sacas factor comun 2

x = [2(8 + / - √23)] / 2 Simplificas el 2

x = 8 + / - √23

x1 = 8 - √23

x2 = 8 + √23

Solucion.

(8 + √23 , 8 - √3).