QuímicaBásico1 respuestas

Ayudaaaaaa por favor?

Ayudaaaaaa por favor! Calcular la molaridad de una disolución de HNO3 al 36. 7% y d = 1. 225g / ml.

En resumen

Mm HNO3 = 63 g / mol M = 1. 225 g x 1000 mL x 36. 7 g disolución x 1 mol HNO3 ```````````` ````````````` ```````````````````````` `````````````````` 1 mL 1 L 100 g disolución 63 g HNO3 M = 7. 136 molar.

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Natanbonates9429
9

Mm HNO3 = 63 g / mol

M = 1.

225 g x 1000 mL x 36.

7 g disolución x 1 mol HNO3 ```````````` ````````````` ```````````````````````` `````````````````` 1 mL 1 L 100 g disolución 63 g HNO3

M = 7.

136 molar.