Ayudaaaaaa por favor?
Ayudaaaaaa por favor! Calcular la molaridad de una disolución de HNO3 al 36. 7% y d = 1. 225g / ml.
Ayudaaaaaa por favor! Calcular la molaridad de una disolución de HNO3 al 36. 7% y d = 1. 225g / ml.
En resumen
Mm HNO3 = 63 g / mol M = 1. 225 g x 1000 mL x 36. 7 g disolución x 1 mol HNO3 ```````````` ````````````` ```````````````````````` `````````````````` 1 mL 1 L 100 g disolución 63 g HNO3 M = 7. 136 molar.
Mm HNO3 = 63 g / mol
M = 1.
225 g x 1000 mL x 36.
7 g disolución x 1 mol HNO3 ```````````` ````````````` ```````````````````````` `````````````````` 1 mL 1 L 100 g disolución 63 g HNO3
M = 7.
136 molar.
Espero haberte ayudado, cualquier duda preguntame y con gusto te responderé sobre este tema.
MOLARIDAD = MASA / VOLUMEN MOLARIDAD = 16 / 0. 2 = 80 GR / L.
Mm H2SO4 = 98 g / mol 1 litro = 270 ml de H2SO4 d = m x v masa = 1. 198 g / mL x 270 mL = 323. 46 g M = 1. 198 g x 1000 mL x 1 mol x 27 g ``````````` ````````````` ``````` ```````` 1 mL 1 L 98 g 100 g M = 3. 30 mol / L…